●●５次方程式の解の公式●●
x^120 = 1の解
x = cos(2π(0/120)) + i * sin(2π(0/120)) = 1
x = cos(2π(1/120)) + i * sin(2π(1/120)) = ((√(8+2√(7+√5+√(30+6√5)))))/4 + (((√(8-2√(7+√5+√(30+6√5)))))/4)i
x = cos(2π(2/120)) + i * sin(2π(2/120)) = √(7+√5+√(30+6√5))/4 + ((√(30-6√5)-√5-1)/8)i
x = cos(2π(3/120)) + i * sin(2π(3/120)) = √(8 + 2√(10 + 2√5))/4 + (√(8 - 2√(10 + 2√5))/4)i
x = cos(2π(4/120)) + i * sin(2π(4/120)) = (√(30+6√5)+√5-1)/8 + (√(7-√5-√(30-6√5))/4)i
x = cos(2π(5/120)) + i * sin(2π(5/120)) = (√6+√2)/4 + (((√6-√2)/4)i
x = cos(2π(6/120)) + i * sin(2π(6/120)) = √(10 + 2√5)/4 + ((√5 - 1)/4)i
x = cos(2π(7/120)) + i * sin(2π(7/120)) = ((√(8+2√(7-√5+√(30-6√5)))))/4 + (((√(8-2√(7-√5+√(30-6√5)))))/4)i
x = cos(2π(8/120)) + i * sin(2π(8/120)) = (√(30-6√5)+√5+1)/8 + (√(7+√5-√(30+6√5))/4)i
x = cos(2π(9/120)) + i * sin(2π(9/120)) = √(8 + 2√(10 - 2√5))/4 + (√(8 - 2√(10 - 2√5))/4)i
x = cos(2π(10/120)) + i * sin(2π(10/120)) = √3/2 + (1/2)i
x = cos(2π(11/120)) + i * sin(2π(11/120)) = ((√(8+2√(7+√5-√(30+6√5)))))/4 + (((√(8-2√(7+√5-√(30+6√5)))))/4)i
x = cos(2π(12/120)) + i * sin(2π(12/120)) = (√5 + 1)/4 + (√(10 - 2√5)/4)i
x = cos(2π(13/120)) + i * sin(2π(13/120)) = ((√(8+2√(7-√5-√(30-6√5)))))/4 + (((√(8-2√(7-√5-√(30-6√5)))))/4)i
x = cos(2π(14/120)) + i * sin(2π(14/120)) = √(7-√5+√(30-6√5))/4 + ((√(30+6√5)-√5+1)/8)i
x = cos(2π(0/120)) + i * sin(2π(0/120)) = 1
x = cos(2π(1/120)) + i * sin(2π(1/120)) = ((√(8+2√(7+√5+√(30+6√5)))))/4 + (((√(8-2√(7+√5+√(30+6√5)))))/4)i
x = cos(2π(2/120)) + i * sin(2π(2/120)) = √(7+√5+√(30+6√5))/4 + ((√(30-6√5)-√5-1)/8)i
x = cos(2π(3/120)) + i * sin(2π(3/120)) = √(8 + 2√(10 + 2√5))/4 + (√(8 - 2√(10 + 2√5))/4)i
x = cos(2π(4/120)) + i * sin(2π(4/120)) = (√(30+6√5)+√5-1)/8 + (√(7-√5-√(30-6√5))/4)i
x = cos(2π(5/120)) + i * sin(2π(5/120)) = (√6+√2)/4 + (((√6-√2)/4)i
x = cos(2π(6/120)) + i * sin(2π(6/120)) = √(10 + 2√5)/4 + ((√5 - 1)/4)i
x = cos(2π(7/120)) + i * sin(2π(7/120)) = ((√(8+2√(7-√5+√(30-6√5)))))/4 + (((√(8-2√(7-√5+√(30-6√5)))))/4)i
x = cos(2π(8/120)) + i * sin(2π(8/120)) = (√(30-6√5)+√5+1)/8 + (√(7+√5-√(30+6√5))/4)i
x = cos(2π(9/120)) + i * sin(2π(9/120)) = √(8 + 2√(10 - 2√5))/4 + (√(8 - 2√(10 - 2√5))/4)i
x = cos(2π(10/120)) + i * sin(2π(10/120)) = √3/2 + (1/2)i
x = cos(2π(11/120)) + i * sin(2π(11/120)) = ((√(8+2√(7+√5-√(30+6√5)))))/4 + (((√(8-2√(7+√5-√(30+6√5)))))/4)i
x = cos(2π(12/120)) + i * sin(2π(12/120)) = (√5 + 1)/4 + (√(10 - 2√5)/4)i
x = cos(2π(13/120)) + i * sin(2π(13/120)) = ((√(8+2√(7-√5-√(30-6√5)))))/4 + (((√(8-2√(7-√5-√(30-6√5)))))/4)i
x = cos(2π(14/120)) + i * sin(2π(14/120)) = √(7-√5+√(30-6√5))/4 + ((√(30+6√5)-√5+1)/8)i
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