1〜5を使って2000までも目指すスレ

このエントリーをはてなブックマークに追加
997132人目の素数さん:02/03/07 15:24
2get。前スレの恨みを晴らすべく、2000は慎重にということで(w
5!+1+43^2 = 1970
5-2+(3!)!!*41 = 1971
5!!*132-4!! = 1972
53+(4!!)!/21 = 1973
(3!)!+1254 = 1974
5*((4!!)!!-2-13) = 1975
52*(41-3) = 1976
5*((4!!)!!+12)-3 = 1977
5!!*132-√4 = 1978
31*((4!!)^2)-5 = 1979
5!!*(134-2) = 1980
541+(3!)!*2 = 1981
√4+5!!*132 = 1982
3*21+5*(4!!)!! = 1983
4!!*(251-3) = 1984
4^5+31^2 = 1985
2*(4^5-31) = 1986
2+5*((4!!)!!+13) = 1987
4!!+5!!*132 = 1988
51*(42-3) = 1989
5*(14+(2^3)!!) = 1990
3!*((4!!)!!-52)-1 = 1991
4!*(52+31) = 1992
25+(3!)!!*41 = 1993
45^2-31 = 1994
21*((3!)!-5^4) = 1995
(4!!)!!+52*31 = 1996
2^(4!!+3)-51 = 1997
54*(1+(3!)^2) = 1998
(5^3)*(4^2)-1 = 1999
(5^3)*(4+12) = 2000
悪あがき。
999132人目の素数さん:02/03/07 15:25
前スレ999で終わっちゃったよ(w
15*4*32 = 1920
31+2*(5+4)!! = 1921
31*(5!+4)/2 = 1922
4!!*(3^5)-21 = 1923
52*(4!+13) = 1924
(3!)!+5*241 = 1925
321*(√(5+4))! = 1926
41*(5!!+32) = 1927
241*(5+3) = 1928
((4!!)!!+21^3)/5 = 1929
(45-1)^2-3! = 1930
2315-(4!!)!! = 1931
42*(5!!+31) = 1932
(45-1)^2-3 = 1933
14+5*(2^3)!! = 1934
215*√(3^4) = 1935
(45-13!!)^2 = 1936
5!!+2*√(31^4) = 1937
3*(21+5^4) = 1938
3+(45-1)^2 = 1939
4*(2*(3^5)-1) = 1940
5+(3+41)^2 = 1941
3!+(45-1)^2 = 1942
(3!)!!*41-25 = 1943
12*54*3 = 1944
1+54*((3!)^2) = 1945
2*(1+4*(3^5)) = 1946
(4!!)!!+3*521 = 1947
4*(1+2*(3^5)) = 1948
5*(4!!)!!-2-31 = 1949
325*(4-1)! = 1950
31+5*(4*2)!! = 1951
2*(31+(5+4)!!) = 1952
21*(45+(3!)!!) = 1953
514+(3!)!*2 = 1954
35+(4!!)!/21 = 1955
12*(5!+43) = 1956
32+5*((4!!)!!+1) = 1957
(5!-31)*(4!-2) = 1958
4!!*(2+3^5)-1 = 1959
245*(3+1)!! = 1960
41+5*(2^3)!! = 1961
√(3^14)-(5!!)^2 = 1962
41*(3*2)!!-5 = 1963
5*((4!!)!!+3^2)-1 = 1964
(3!)!+1245 = 1965
41*(3!)!/5!!-2 = 1966
2351-(4!!)!! = 1967
5!+4!!*231 = 1968
4^5+(12-3)!! = 1969
もいっちょ。
10011001
このスレッドは1000を超えました。
もう書けないので、新しいスレッドを立ててくださいです。。。