make a math problem

make a math problem in english

>>1
What's one plus one?

>>1
Zeusとか名乗ってどんだけ中二病なの？ｗｗｗ

i assume about high school or college level math probrem

in english!!!!

>>4
What's the integral of x squared with respect to x over the interval [0,100]?

>>3
write in english only!!!(i angry!!!

>>7
>>6

it up the intelligence quotient that make a math problem in english
and solve it.
why?
it is different that solve a japanese math problem from make a math problem.

i am american college student.
i study math in college.

>>10
You're not American.

>>9
Write correct English!
What did you learn about grammar at school?

>>12
Hey, someone else is watching this shitty thread! Talk to me.

Let S be a set of rational numbers with
the following properties:1) 1/2 is an element of S2)
If x is an element of S, then both 1/(x+1) is an element of S
and x/(x+1) is an element of SProve that S contains all rational
numbers in the interval 0<x<1.

>>14
If x=m/n then 1/(x+1)=n/(m+n) and x/(x+1)=m/(m+n).

So, let q=m/n be an arbitrary rational number from the interval (0,1). Obviously we may assume that GCD(m,n)=1.
Therefore by Euclidean Algorithm there is a finite sequence of rational numbers {q_i=m_i/n_i}_{i=1}^{n} such that q_1=1/2, q_n=q and for every i=1,...,n-1 one of the following holds:

m_{i+1}=m_i and n_{i+1}=m_i+n_i,

or

m_{i+1}=n_i and n_{i+1}=m_i+n_i.

It means that q_{i+1}=q_i/(q_i+1) or q_{i+1}=1/(q_i+1). And hence q_i \in S for all i. In particular, q=q_n \in S. The problem is solved.

>>13
Hey, who are you?

>>16
A random person. Who're you?

>>17
I'm NEET. lol

>>18
Haha, nice. I graduated from university in June, don't start working until September. So I guess I'm a NEET too, just for the summer.

>>17
I'm just nobody.
What the heck is this crap thread?

The intersection of a unit cube and a plane passing through its center is a regular hexagon.　What is the area of the regular hexagon?

>>20
Who knows. There's five new shitty threads every fucking day, it's retarded.

>>21
3√3/4

>>21
You should only shout "Hexagon" like stupid TV shows.

>>21
どうだ？

３√３
―――
　　４

>>25
Beat you. >>23

Suppose we have such an equivalence relation is S. Given an element x of S, let C_x consist of all
elements of S which are equivalent to x.
Then all elements C_x are equivalent to one another , as follows from our three properties.
Furthermore, you will also verify that if x,y are alements of S, then either C_x=C_y , or C_x,C_y have
no elements in common. Each C_x is called an equivalence class. We see that our equivalence relation
determines a decomposition of S into disjoint equivalence classes.
Our first example of the notion of equivalence relation will be the notion of congruence.
Let n be a positive integer. Let x,y be integers. We shall say that x is congruent to y modulo n
if there exists an integer m such that x-y=mn. This also means that x-y is divisible by n. We write the relation of congruence in the form:
x≡y mod n.
It is then immediately verified that this is an equivalence relation , namely that the
following properties are satisfied:

1.For any positive integer k , give a proof of 7^k≡1 mod 6

>>27
７のｎ乗を６で割ったとき、１余ることを証明すればいいんだね。

簡単さ。

（例）
　　７＾２＝４９　　４９／６＝８・・・１　　証明終わり。

>>28
すっげぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇ
ぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇ
ぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇ
ぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇ
ぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇ
ぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇぇ！！！！！

Let　ｘ1,ｘ2、....,x2006 be positive real numbers satisfying the condition

1/(1+�]1)+1/(1+�]2）＋・・・・・＋１/(1+x2006)=1

find the minimal possible value of the expression ｘ1・ｘ2・・・・x2006

>>28
write in english!!!
your answer is fault.

find all positive odd integers n for which there exist odd integers �]1,�]2....�]n such
that

�]1^2+�]2^2+.......�]n^2＝n＾４

is it to difficult to make a math problem?

hosyu

age

age

Monday, July 14, 2008
President Bush delivered a statement on the 10th anniversary of
the International Religious Freedom Act at the White House.
He expressed his continued support for the IRFA, discussed
how bipartisan efforts in implementing the IRFA have elevated
and institutionalized the promotion of religious freedom and
the progress made to date, and called for renewed efforts to
implement the IRFA.

The International Religious Freedom Act represented a bipartisan
effort by Members of Congress, human rights groups, and religious
leaders and communities to end religious persecution and intolerance.
The main goals of the legislation were to provide the mandate,
resources and tools to raise public awareness of religious
persecution; generate consistent, effective United States Government
action to end persecution and promote religious freedom; ensure that
promotion of religious freedom was an integral component of our
foreign policy; and create strong incentives for change by
governments violating religious freedom.

President Bush also made a statement discussing the need for
Outer Continental Shelf exploration to ease our dependance on
foreign oil.

age

age

junior　high　school　math　problem　　ｏｋ！

Let k be a natural number such that

k+1 is divisible by 24. Prove that
the sum of all divisors of k (which are natural numbers) is
divisible by 24.

age

hosyu

Find all pairs of nonnegative integer numbers (m,n)
satisfying the equality
(m-n)^2(n^2-m)=4m^2n

Let k be a natural number such that k+1 is divisible by 24. Prove that the sum of all divisors of k (which are natural numbers) is divisible by 24.

Find all integers n such that the set {1,2,3,4, ....,n} can be written as the disjoint union of the subsets A , B , C whose sum of elements are equal.

Let p be a prime number exceeding 5. Prove that there exists a number k such that each digit in the decimal representation of pk is 1 :

pk = 1111...1

There is a finite number of towns in a country.
They are connected by one direction roads.
It is known that for any two towns, one of them can be reached
from the other one. Prove that there is a town such that all
the remaining towns can be reached from it.

it up the intelligence quotient to make a math problem in english
and solve it.

it up the intelligence quotient to make a math problem in english
and solve it.

it grow　ｕｐ　 the intelligence quotient（Ｄ�TＱ） to make a math problem in english
and solve it.

it grow　ｕｐ　 the intelligence quotient（Ｄ�TＱ） to make a math problem in english
and solve it.

it grow　ｕｐ　 the intelligence quotient（Ｄ�TＱ） to make a math problem in english
and solve it

it grow　ｕｐ　 the intelligence quotient（Ｄ�TＱ） to make a math problem in english
and solve it

Fractal Function
Let F(x) be a non-decreasing function for all x in [0 1], such that

2F(x/3)=F(x) and F(x)+F(1-x)=1

1. Find F(173/1993) and F(1/13).

2. If possible give a general algorithm to find F(x) for any x.

Other questions:

3. Is F(x) uniquely determined(in [0,1])?

4. Is F(x) continuous(in [0,1])?

ｐ，ｑ，ｒを自然数とする。
直角三角形ＡＢＣの斜辺をｒとする。
この三角形の他の二辺をｐ、ｑとする。
このとき、Ｐ＾２＋ｑ＾２が奇数になるための
条件を求めよ。

what is the 10^10000th number of pi?

>>57
your ＤＩＱ grow up 30point

http://www.enjoykorea.jp/tbbs/read.php?board_id=pfree&nid=370806&start_range=370806&end_range=370821
各国英語比較

「ｐ、ｑ、ｒ　are　natural　numbers　ａｎｄ　satisfing　ｐ≦ｑ≦ｒ．
ａｎｄ、ｐ、ｑ are even　numbers and ｒ is odd number.
find the most small positive integral number
satisfing √ｐ×√ｑ×√ｒ」

三角形ＡＢＣの辺ＢＣをｍ：ｎに内分する点をＦとし、
三角形ＡＢＣの辺ＡＣをｌ：ｋに内分する点をＨとする。
また、三角形ＡＢＣの辺ＡＢをｓ：ｒに内分する点をＧとする
Ｆが辺ＢＣ上をＢからＣへ動き、Ｈが辺ＡＣ上をＡからＣへ動き、
Ｇが辺ＡＢ上をＡからＢへと動くとき、
三角形ＧＨＦが最大値をとるときの、条件を、ｍ、ｎ、ｋ、ｌ、ｓ、ｒの式で
表せ。

hostyu

ほしゅ

it grow　ｕｐ　 the intelligence quotient（Ｄ�TＱ） to make a math problem in english
and solve it

Sorry for the duplicating post.
No one replied to my questions on another thread but
I expect some people here know the answers.

What I would like to know are suitable expression in English of
each component in a numerical formula like:

1 + 2 + 3 + 4 = 10

My questions are which expression is correct, or better.

1 + 2 + 3 + 4 → formula? expression?
1, 2, 3, 4 → number? figure?
10 → result? answer?

it grow　ｕｐ　 the intelligence quotient（Ｄ�TＱ） to make a math problem in english
and solve it

it grow　ｕｐ　 the intelligence quotient（Ｄ�TＱ） to make a math problem in english
and solve it

>>65
1 + 2 + 3 + 4 → expression
1, 2, 3, 4 → term
10 → answer or result, both are equal

>>65
1 + 2 + 3 + 4 → expression
1, 2, 3, 4 → term
10 → answer or result, both are equal

>>45
Interesting problem, could you give a hint?

>>70
Your　ＤＩＱ　grow　ｕｐ　to solve　the　math　problem　hintless．

the intelligence quotient　of the white is 115
the intelligence quotient　of the yellow is 110(japanese is 118)
the intelligence quotient　of the black is 90

if grow up the intelligence quotient,your work proceed successfully.

the black is nearly intellectual disability.
under 70 is intellectual disability

the ＤＮＡ　ｏｆ　the　white　and　black　is　different．

make　ａ　math　problem　about　formula　of　quadratic　equation．

ｐ，ｑ，ｒ are natural numbers.
make a math problem about integral numbers.

it grow　ｕｐ　 the intelligence quotient（Ｄ�TＱ） to make a math problem in english
and solve it

it grow　ｕｐ　 the intelligence quotient（Ｄ�TＱ） to make a math problem in english
and solve it

it grow　ｕｐ　 the intelligence quotient（Ｄ�TＱ） to make a math problem in english
and solve it

it grow　ｕｐ　 the intelligence quotient（Ｄ�TＱ） to make a math problem in english
and solve it

it grow　ｕｐ　 the intelligence quotient（Ｄ�TＱ） to make a math problem in english
and solve it

make a math problem in english

make a math problem in english

plz make a math problem which's suitable for an average japanese 11th grader,
and post it. an easy probability problem is good as a step 1.

problemじゃなくてquestionだろ。
初歩的な間違いで恥ずかしい。

it grow　ｕｐ　 the intelligence quotient（Ｄ�TＱ） to make a math problem in english
and solve it

>>84

How's this:

A bag contains 3 red cubes, 12 green cubes, and 4 blue cubes. If you draw two cubes out, what is the probability that they will be the same color?

age

Let m and n be integers greater than 1.
Consider an m*n rectangular grid of points in the plane.
Some k of these points are colored red in such a way that
no three red points are the vertices of a right-angled triangle,
two of whose sides are parallel to the sides of the grid.
Determine the greatest possible value of k for any given values of
m,n > 1.

あげ

あげ

私は朝鮮人です★裁判ですよ♪スルガ銀行
スルガ銀行は違法銀行です。
スルガ銀行は個人情報保護法１７条および１６条に違反し，機微情報の取得および目的外利用を行いました。
裁判では，機微情報の目的外利用についてスルガ銀行支店長の自白が記録された録音テープが提出されました。
スルガ銀行は，支店長の自白について，のちに「冷静さを失った支店長の言い間違いです。」などとごまかした。
この違法行為はスルガ銀行が特定集団だけを標的とした違法規定によるものであり，
したがって，偶発的・個別的な違法行為ではなく，スルガ銀行による意図的・組織的・継続的な違法行為です。
すなわち，スルガ銀行の預金口座開設規定自体が違法規定です。
スルガ銀行はこの事実を隠すため，裁判において前記違法規定の提出を拒否しました。
また，スルガ銀行は銀行法施行規則１３条の６の７等で禁止されている機微情報の利用を違法に行い，
さらに，利用目的の事前明示義務に違反しました。したがって，個人情報保護法１８条２項違反です。
スルガ銀行は裁判で「本人確認が完了しないときは個人情報保護法１８条は適用されない」などとウソをつきました。
スルガ銀行は違法行為の隠蔽のため，裁判で前記違法規定の提出を拒否しました。
http://360.yahoo.com/victimsagainstillegalbanksuruga　違法銀行スルガと闘う被害者の会VAIBS

Let m and n be integers greater than 1.
Consider an m*n rectangular grid of points in the plane.
Some k of these points are colored red in such a way that
no three red points are the vertices of a right-angled triangle,
two of whose sides are parallel to the sides of the grid.
Determine the greatest possible value of k for any given values of
m,n > 1.

Find all pairs of nonnegative integer numbers (m,n)
satisfying the equality
(m-n)^2(n^2-m)=4m^2n

age

write in chat in English thread. nobody see this thread and
answer.
I don't have the will to see several threads.

>>96
why?

Nobodody bothers to come here and answer your questions in
English. People increase the chances to see and answer your questions
in chat in English thread.

age

100get

agw

age

age

ほしゅ

age

あげ

age

age